3 table and 4 chair cost is 3300 and 2 table and 10 chair cost 3300 find the cost of one table and one chair
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let Table = T
Chair = C
According to Question
3T + 4C = 3300 Eq-i
2T + 10C = 3300 Eq-ii
Multiply equation i by 2 and equation ii by three we get
6T + 8C = 6600
6T + 30C = 9900
now substract them
we get
22C = 3300
C = 150
price of 1 chair is rs 150
now put this value in eq ii
2T + 10(150) = 3300
2T = 1800
T = 900 Rs.
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