Question

3/tan^2 30°+1/sin^2 45°-sin^2 60°

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

$= \frac{3}{ {tan}^{2} 30\degree} + \frac{1}{ {sin}^{2}45 \degree } - {sin}^{2} 60 \degree \\ \\ = \frac{3}{ {( \frac{1}{ \sqrt{3} }) }^{2} } + \frac{1}{ {( \frac{1}{ \sqrt{ 2}} })^{2} } - {( \frac{ \sqrt{3} }{2} })^{2} \\ \\ = \frac{3}{ \frac{1}{3} } + \frac{1}{ \frac{1}{2} } - \frac{3}{4} \\ \\ = 9 + 2 - \frac{3}{4} \\ \\ = 11 - \frac{3}{4} \\ \\ = \frac{41}{3}$