Question

3 tan 30° sec 45° + 3 tan 60° sec 30°, Evaluate.​

Answer 1

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$3 \tan(30) \sec(45) + 3 \tan(60) \sec(30) \\ = 3 \times \sqrt{3} \times \sqrt{2} + 3 \times \frac{1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{2} \\ = 3 \sqrt{6} + \frac{3}{2} \\ = 54 + \frac{3}{2} \\ = \frac{108 + 3}{2}$

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Answer 2

Answer:

$3 \tan(30) \sec(45) + 3 \tan( 60) \sec(30) \\ = 3 \times \frac{1}{ \sqrt{3} } \times \sqrt{2} + 3 \times \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ = \sqrt{6} + 6 \\ = \sqrt{6} (1 + \sqrt{6} )$