Question

√3 (tan 40° - tan 10) - tan10 tan40​

Answer 1

Answer:

Hi,

Sin 18°/cos 72° + V3 [tan10 tan 30 tan 40 tan 50 tan 80]

=Sin 18°/cos(90-72) + v3 [tan10 tan 30 tan 40 tan(90-50) tan(90-80)]

=Sin 18°/Sin 18+ V3 [tan10 tan 30 tan 40 cot40 cot10]

=1+ v3 [tan10 tan 30 tan 40 1/tan40 1/ tan10]

=1+ v3 [tan 30]

=1+ v3 [1/v3]

=1+1 = 2

hope it is helpful to you

god bless your heart ☺❤❣