Question

3 tan 45+ tan square 60​

Answer 1

$3 \times 1 + (\sqrt{3}) {}^{2} \\ 3 + 3 \\ = 6$

$tan 45 = 1 \\ tan 60 = \sqrt{3} \\ so \: > tan {}^{2} 60 = ( \sqrt{3} ) {}^{2}$

Answer 2

Solution :-

$3 \tan(45) + {tan}^{2} 60 \\ \\ 3 \times 1 + ( { \sqrt{3}) }^{2} \\ \\ 3 + 3 = 6$

Note :-

tan 45° = 1

tan 60° = √3

Hope it's helpful for you !!!