Math, asked by lalbahadursubba3007, 6 months ago

3(tan square 30°)-8(sin square 45°+cos square 30°)=0

Answers

Answered by rajeevr06
0

Answer:

3 \times ( \frac{1}{ \sqrt{3} } ) {}^{2}  - 8 \times ( \frac{1}{ \sqrt{2} } ) {}^{2}  + ( \frac{ \sqrt{3} }{2} ) {}^{2}  = 1 - 4 +  \frac{3}{4}  =  \frac{ - 12 + 3}{4}  =  -  \frac{9}{4}

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