Question

3 tan square theta = 2 sec square theta + 1​

Answer 1

Identity used:

$\sec {}^{2} ( \theta ) - \tan {}^{2} ( \theta ) = 1$

Solved in detail:

$\ tan{}^{2} ( \theta ) = 2\sec {}^{2} ( \theta ) - 2\tan {}^{2} ( \theta ) + 1$

$\tan {}^{2} ( \theta ) = 2 + 1$

$\tan {}^{2} ( \theta ) = 3$

$\tan ( \theta ) = \sqrt{3}$

$\theta = 60$

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