Question

3 tan theta = 3 sin theta then
Sin²theta -cos²theta =​

Answer 1

Answer:

-1

Step-by-step explanation:

3tanФ = 3sinФ

3sinФ/cosФ = 3sinФ

1/cosФ= 1

∴ cosФ=1

Now, sin²Ф - cos²Ф

wkt, sin²Ф + cos²Ф = 1

       ∴sin²Ф= 1 - cos²Ф

Substituting the values of sin²Ф, we have

(1 - cos²Ф) - cos²Ф

⇒ 1 - cos²Ф - cos²Ф

⇒1 - 2cos²Ф

wkt cos²Ф = 1

Now, substituting the value in the above equation, we have

1 - 2(1)

⇒1 - 2

⇒ -1

Hope this helped you!

Answer 2

Answer:

Step-by-step explanation

1 .3(sin/cos) theta =3 sin theta

2. sin/cos theta= sin theta

3. 1/cos theta= 1

4. cos theta= 1

from the equation....

1. Sin²theta -cos²theta=1

2. Sin²theta -(1)=1

3. Sin²theta = 0

4. sin theta=$\sqrt{0$

5. sin theta = 0

so...

$0^{2}$ - $(-1)^{2}$=0

=-1