Question

3 Tan² 45 - Sin²60 - 1/2cot² 30 + 1/8sec²45​

Answer 1

Here is your answer✌️✌️

$3tan^245°-sin^260°-1/2cot^230°+1/8sec^245°$

put value -

$3×(1)^2-(√3/2)^2- (1/√2)^2 *3 + 1/8*(√2)^2$

3*1/2- 3/2 - 1/2*3 +1/8*2

3/2 -3/4 +1/4

6-3+1÷4

4/4

1

✍️✍️ please mark it brainlist answer..

Answer 2

Here is your answer:(•‿•)(•‿•)

$3tan^2 45° -sin^260° -1/2cot^2 30°$

$+2/8sec^2 45°$

$3/2-3/4 - 3/2 + 1/4$

4/4

1

please mark it brainlist answer.......