3(tan72/cot18)-2(sin54/36cos)
Find the value?????
Answers
Answered by
0
pls refer to the attachment :)
Attachments:
vishal373y:
Thankxs guyz
my pleasure :p
Answered by
1
Answer:
Step-by-step explanation:
3(tan72/cot18)-2(sin54/cos36)
=>3 (tanA/cot(90°-72))-2(sin54/cos(90°-54))
=3(tan72/tan 72)-2(sin54/sin54)
=3-2
=1 Answer
Hope it helps you buddy ☺
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