Question

3(tan72/cot18)-2(sin54/36cos)
Find the value?????

Answer 1

pls refer to the attachment :)

Answer 2

Answer:

Step-by-step explanation:

3(tan72/cot18)-2(sin54/cos36)

=>3 (tanA/cot(90°-72))-2(sin54/cos(90°-54))

=3(tan72/tan 72)-2(sin54/sin54)

=3-2

=1 Answer

Hope it helps you buddy ☺