Question

3(tan72/cot18)-2(sin54/cos36)

Answer 1

Answer:

3(tan 72/ cot 18) - 2(sin 54 /cos 36)              ------------------------------A.

Now,

tan 72 = cot (90- 18) = cot 18                          -----------------------------  1.

also,

sin 54 = cos (90- 36) = cos 36                          ----------------------------2.

Now putiing 1. and 2. in A, we get;

3(cot 18 / cot 18) - 2 (cos 54 / cos 54)

Or,

3 - 2 = 1

So the answer is 1  .

Hope this helps...