Math, asked by ap452733, 7 months ago

√3 tanQ= 3 sin Q find sin²Q -Cos²Q

Answers

Answered by unique1man

1

Answer:

tanQ=3sinQ/√3

sinQ/cosQ=3sinQ/√3

sinQ/cosQ=(√3)²sinQ/3

SINQ/COSQ=3SINQ

COSQ=3SIN²Q

NOW,

SIN²Q-COS²Q

SIN²Q-(3SIN²Q)²

Step-by-step explanation:

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