3 taps of equal flow fill a tank in 2 hours. if two taps are not working,how time to take the tank full with 2 tap?
Answers
Answer:
Step-by-step explanation:
Your taps are unequal (you did not say anything about them) or the water pressure varied from time to time when you did your tests (this is quite normal). Therefore there is no physically correct answer.
Let us mark the flow rate of the tap (e.g. liters per hour) by F and the volume of the tank by V (e.g. liters). From the first statement we get
3 x 2 h x F = V (1st)
From the second one we get
2 x 5 h x F = V (2nd)
Solving for F we get
F = V/6 h (1st) or F = V/10 h (2nd),
which indicates that F was not constant.
Maybe I misunderstood your system. Perhaps you had a tank-to-tank transfer where the variation of liquid pressure actually can be calculated if you know how much liquid there originally was in the source tank, the full geometry of the system, and the viscosity of the liquid.