3 terms are in AP such that their sum is 18. The sum of the first 2 terms is six more than the sum of the last 2 terms. Find the last term?
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Answer:
LAST TERM IS 3
Step-by-step explanation:
let the 3 terms be a-d , a , a+d .These are in AP
given that their sum is 18 , therefore.
a-d + a + a+d = 18
3a =18
a = 6
also, a-d + a = 6+ a + a+d
d = -3
therefore the last number is a+d = 3 .
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Lets assume the AP is a−d,a,a+d.
then,
a−d+a+a+d=18
3a=18⇒a=6
so the series is 6-d , 6 , 6+d
6-d + 6 = 6 + 6 + d + 6
2d = -6
d = -3
now the AP series is 9 , 6 , 3
so the last term is 3 .
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