Question

3
$3(7x + 1 \div 5x - 3) - 4(5x - 3 \div 7x + 1) = 11$
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Answer 1

Simplify:

Step-by-step explanation:

Given value:

$3(7x+1\ \div \ 5x-3) - 4(5x-3 \ \div 7x+1) =1\\\\3(\frac{7x+1}{ 5x-3}) - 4(\frac{5x-3}{ 7x+1}) =1\\\\\frac{21x+3}{ 5x-3} -( \frac{20x-12}{ 7x+1}) = 1\\\\\frac{(21x+3) (7x+1) - ((20x-12)(5x-3) )}{ (5x-3) (7x+1)} = 1\\\\\frac{(147x^2+21x+21x+3) - ((100x^2-60x-60x+36))}{ (5x-3) (7x+1)} = 1\\\\\frac{(147x^2+42x+3) - (100x^2-120x+36)}{ (35x^2-21x+5x-3) } = 1\\\\\frac{147x^2+42x+3 - 100x^2+120x-36)}{(35x^2-16x-3)} = 1\\\\\frac{47x^2+162x-33)}{(35x^2-16x-3)} = 1\\\\47x^2+162x-33= 11(35x^2-16x-3)$

$47x^2+162x-33= 385x^2-176x-33 \\\\385x^2-47x^2-33+33= 162x+176x\\\\358x^2=358x\\\\\frac {x^2}{x}=\frac{358}{358}\\\\x=1$

Learn more:

• Simplify: https://brainly.in/question/8923602

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