Question

3
$3 \sqrt{8 \: is \: a \: rational \: number \: or \: irrational \: }$
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Answer 1

Step-by-step explanation:

$Answer:</p><p></p><p>\sqrt{2 \times \sqrt{8} } \: is \: an \: irrational \: number.2×8isanirrationalnumber.</p><p></p><p>Step-by-step explanation:</p><p></p><p>We know that ,</p><p></p><p>\begin{gathered}\sqrt{8} \: is \:not \: a \: perfect \: square \: \\ and \: hence \: \\ it \: is \: an\: irrational \: number.....\end{gathered}8isnotaperfectsquareandhenceitisanirrationalnumber..... So any number multiplied to an irrational number [except 0 ] is irrational. THEREFORE,</p><p></p><p>\sqrt{2 \times \sqrt{8} } \: \: is \: an \: irrational \: number.2×8isanirrationalnumber.</p><p></p><p>My Answer is ABSOLUTELY CORRECT .... My GUARANTEE ..... Am I Right or Am I Right ....</p><p></p><p>$