Question

3.The 11th term and the 21st term of an A.P. are 16 and 29 respectively, then find the 41th term of that A.P.

Answer 1

hi..


a11 = 16
a21 = 29

a + 10d = 16___1
a + 20d = 29
- - -
__________
10d = 13
d = 1.3


from 1

a + 13 = 16
a = 3


a41 = a + 40d
= 3 + 40×1.3
=3 + 52

a41 = 55

Answer 2

The 11th term and the 21st term of an A.P. are 16 and 29 respectively,
a+10d=16
a+20d=29
d=1.3
a=3
the 41th term of that A.P.
a41=55




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