3.The 11th term and the 21st term of an A.P. are 16 and 29 respectively, then find the 41th term of that A.P.
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Answered by
4
hi..
a11 = 16
a21 = 29
a + 10d = 16___1
a + 20d = 29
- - -
__________
10d = 13
d = 1.3
from 1
a + 13 = 16
a = 3
a41 = a + 40d
= 3 + 40×1.3
=3 + 52
a41 = 55
a11 = 16
a21 = 29
a + 10d = 16___1
a + 20d = 29
- - -
__________
10d = 13
d = 1.3
from 1
a + 13 = 16
a = 3
a41 = a + 40d
= 3 + 40×1.3
=3 + 52
a41 = 55
MADBRO:
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Answered by
3
The 11th term and the 21st term of an A.P. are 16 and 29 respectively,
a+10d=16
a+20d=29
d=1.3
a=3
the 41th term of that A.P.
a41=55
t
a+10d=16
a+20d=29
d=1.3
a=3
the 41th term of that A.P.
a41=55
t
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