Question

3. The altitude of a right angle triangle is 7cm less than its base. Its hypotenuse is 13cm. find the other two sides

Answer 1

Answer:

H=13cm

P=(B–7)cm

By Pythagoras theorem, H²=B²+P²

(13)²=(B²)+(B–7)²

169=B²+B²+49–14B

=>B²–7B–60=0

=>B²–12B+5B–60=0

=>B(B–12)+5(B–12)=0

OR (B–12)(B+5)=0

so, B=12cm or 5(discarded)

Therefore, P=5cm

Therefore, Its other two sides are 12cm and 5cm

Answer 2

Answer:

let the base be 'x'

altitude=x+7

hypotenuse =13 cm

By using pythagoras theorem:

equating the values of base altitude and hypotenuse , you will get the value of x as 5

Therefore ;

hypotenuse=13 cm

base=5 cm

altitude=12 cm.

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