Question

3. The amplitude and the time period in a SHM is 0.5 cm and
0.4 s respectively. If the initial phase is a/2 rad, then the
equation of SHM will be
(a) y = 0.5 sin 5nt
(b) y = 0.5 sin 4rt
(c) y = 0.5 sin 2.5nt
(d) y = 0.5 cos 5nt​

Answer 1

Answer:

(d) y = 0.5 cos 5πt​

Explanation:

general equation of SHM from mean position is

y = a sin (ωt+Ф)

acc to question

a = 0.5 cm

T = 0.4 s -> ω = 2π/T = 5π

Ф = π/2

on substituting

we get, y = 0.5 cos 5πt​