3.The angle of depression of a car standing on the plane ground from the top of a 900m high tower is 30^(@).What is the distance of the car from the base of the tower?
Answers
Answered by
1
Answer:
Correct option is C)
In right angle triangle ABC the ∠ACB=30
0
(Angle of depression of a car) and the tower is 75 m high
Let the distance of car from ground is x m
Then tan30
0
=
BC
AB
=
x
75
⇒
3
1
=
x
75
⇒x=75
3
m
Similar questions