Question

3. The angles of a quadrilateral are 2x°, 3 x°, 4 x°, x°. Find the angles.​

Answer 1

Given angles of a quadrilateral are 2x,2x+15,4x−12,3x−0.5

As we know that

Sum of angles in a quadrilateral is 360

⟹2x+2x+15+4x−12+3x−0.5=360

⟹11x=360−2.5

⟹x=

11

357.5

=32.5

2x=2(32.5)=65,2x+15=65+15=80,4x−12=4(32.5)−12=130−12=118,3x−0.5=3(32.5)−0.5=97

So the angles are 65,80,118,97

Answer 2

Answer:

2x=72°

3x=108°

4x=144°

x=36°

Step-by-step explanation:

Given,

Angles of quadrilateral:

2x°, 3x°, 4x°, x°

We know,

Sum of angles of quadrilateral=360°

Thus,

2x + 3x + 4x + x=360°

10x=360°

x=360°/10

x=36°

therefore,

2x= 2× 36°

= 72°

3x= 3× 36°

= 108°

4x= 4× 36°

= 144°

x = 36°