3. The angles of a triangle are (x - 40), (x-20)° and 1/2x -10 angles. Find the value of x
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The sum of measures of angles of a triangles is 180 degrees
∴(x−40)+(x−20)+(x/2−10)=180
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∴5x/2−70
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=180
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∴5x/2=250
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∴5x=500
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∴x=100
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Answer:
By angle sum property, (x-40) + (x-20) + (x/2) = 180
(2x-80+2x-40+x)/2=180
5x-120=360
5x= 480 => x= 96
So the angles of the triangle will be (96-40) = 56, (96-20) = 76 and (96/2) = 48
Thus the angles are 56 degree, 76 degree and 48 degree
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