3. The area of a rectangular site is 96 m². If its length is greater than its breadth by 4 metres. The
length and breadth of the said site are-
a) 10 metres, 6 metres b) 12 m and 8 m c) 8 m and 12 m d) 4 m and 8 m
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Let the breadth of the rectangle be x.
Then atq, length will be x+4
We know that,
Area of Rectangle = Length × Breadth.
Therefore,
→ 96 = (x+4) × x
→ 96 = x(x+4)
→ 96 = x² + 4x
Or
x² + 4x - 96 = 0
Now we will solve this quadratic equation.
We need two numbers , such that their product should be -96 and their sum should be 4.
Numbers are 12 and -8
→ x² + 12x - 8x - 96 = 0
→ x(x+12) - 8(x + 12) = 0
→ (x - 8)(x + 12) = 0
If
x - 8 = 0
Then,
x = 8
Or if
x + 12 = 0
→ x = -12
But since breadth of the rectangle can't be negative, therefore x = 8 is the right answer.
Hence, breadth of the rectangle is x = 8m
And length of the rectangle is → x + 4m → 8m + 4m = 12m
Hence, option b is correct (i.e., 12m and 8m).
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