Question

3. The area of a trapezium ABCD is 69 sq.cm. The length of its bases AB and CD
are 8 cm and 15cm respectively. Find the distance between them.

Pls answer this question by step by step explanation .
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Answer 1

Answer:6 cm

Step-by-step explanation:

area = 69 sqcm

a=8

b=15

height =?

area = h(a+b)÷2

69=h(8+15)÷2

69=h(23)÷2

69÷23×2=h

3×2=h

6cm=h

Answer 2

Answer:

6 cm

Step-by-step explanation:

A= 69 cm²

A= 1/2* ( sum of parallel sides )* h

69 = 1/2* ( 15+8 )* h

69 = 1/2* 23 *h

69* 2/ 23 = h

3* 2/1 = h

h = 6cm

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