3. The area of a trapezium is 1,586 cm² and sum of parallel sides is 122 cm. Find th
distance between two parallel sides.
4.If the area of a trapezium is 28 m?, and two parallel sides are 8 m and 60 d
respectively, find the altitude.
Answers
Answer:1....area of trapezium = 1586 cm²
(1/2) × (sum of parallel sides) × height = 1586 cm²
1/2 × (84+other side) × 26 = 1586 cm²
84+other side = (1586×2)/26
84+other side = 112
other side = 122-84 = 38 cm
2...
given the length of parallel sides of the trapezium are 8m and 60dm respectively.
we know that 10dm = 1m
therefore 60dm = 60/10 = 6m
we have to find the altitude of the trapezium.
formula for the area of trapezium is 1/2 × h ( b1 + b2 ) where "h" is the altitude and b1 and b2 are the parallel sides of the trapezium.
area of the trapezium = 28m²
>> 1/2 × h ( b1 + b2 ) = 28m²
>> h ( 8 + 6 ) = 28/1 × 2/1
>> h ( 8 + 6 ) = 56/1
>> 14h = 56
>> h = 56/14
>> h = 4
hence, the altitude of the trapezium is 4m.
FOLLOW ME
Answer:
3.area=1586cm^2
area=½(sum of parallel sides)×h
1586 =½×122×h
1586/61=h
distance between two parallel sides= 26cm.....
4.area=½(sum of parallel sides)×h
60dm=6m
28=½(8+6)×h
28=½×14×h
28=7h
28/7=h
h= 4m
Step-by-step explanation:
hope it helps you
Mark this as BRAINLIEST...