Question

3. The area of a trapezium is 480 cm2, the distance between two parallel sides is 15 cm and one of the parallel side is 20 cm. The other parallel side is:

A. 20 cm

B. 34 cm

C. 44 cm

D. 50 cm​

Answer 1

Given :-

• Area of trapezium = 480 cm²
• Distance between two parallel sides is 15cm. Means height of trapezium is 15cm.
• One parallel side = 20 cm.

To find :- Other parallel sides.

$\sf\blue{SolutioN:-}$

⇒We know that,

$Area \: of \: trapezium \: = \frac{a + b}{2} \times h$

In which 'a' and 'b' are parallel sides and 'h' is height of trapezium or we can say distance between parallel sides.

So, According to question

⇒480 = 20 + b /2 × 15

⇒480 × 2 = 20 + b × 15

⇒960 = 20 + b× 15

⇒960/15 = 20 + b

⇒64 = 20 + b

⇒64 - 20 = b

⇒44 = b

Hence , Other parallel side is 44 cm.

_______________________

More information:-

• Trapezium is a closed figure.
• It consists of four sides.
• In which 2 sides are parallel.
• And two opposite sides are equal but not parallel.
• Perimeter of trapezium is A + B + C+ D. In which A , B ,C and D are sides of trapezium.
• Area of trapezium is a + b/2×h. In which A and B are parallel sides of trapezium and H is distance between parallel sides.

Answer 2

The area of trapezium is given as

Area= $\frac{1}{2}$ × sum of parallel side × distance between the parallel sides

• Given: area = 480  cm²

           distance between parallel sides = 15 cm

          length of one parallel side = 20cm

• Let the length of the other parallel side be x

putting values in the formula,

480 =  $\frac{1}{2}$ × (20 + x) ×15

  20+ x = 64

    x= 44

The length of other parallel side will be 44 cm

The correct answer will be option c.