Question

3. The area of base of a cylindrical vessel is 300 cm
Water (density = 1000 kg m-3) is poured into it up
to a depth of 6 cm. Calculate : (a) the pressure and
(b) the thrust of water on the base. (8 = 10 m s-).
Ans. (a) 600 Pa, (b) 18 N​

Answer 1

Given:

• Area of base of a cylindrical vessel is 300cm
• Density: 1000 kg m^3
• Depth : 6cm
• g = 10m/s

To Find:

a) the pressure

b) thrust of water on the base

Solution:

a) Here we using the formula of Pressure.

Formula of Pressure: hdg

➡ $\sf\ 0.06 m × 10^3/m^3 × 10m/s^2$

$\dashrightarrow\: \underline{\boxed{\bf{\purple{600 pa}}}}$

•°• Pressure exerted by cylindrical vessel is 600 pa.

b) Here we using the formula of Thrust.

Formula of Thrust : Pressure × Area

➡ $\sf\ 600 pa × 300 × 10^-4m^2$

$\dashrightarrow\: \underline{\boxed{\bf{\purple{18 N}}}}$

•°• The thrust on base is 18 N.

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$\large\underline\bold{Additional\: Information}$

• Pressure is an expression of force exerted on a surface per unit area.
• The standard unit of pressure is the pascal (Pa).
• The total force exerted by the body perpendicular to the surface is known as thrust. S.I unit is (N).

⠀⠀⠀⠀Thrust = Pressure × Area

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