Question

3) The area of the base of a cylinder is 120 sq.cm. Find the volume if its
height is 15cm.​

Answer 1

Step-by-step explanation:

ANSWER:-

Given:-

• The area of the cylinder as 120 cm²
• We need to find the volume , given if its height is 15 cm.

Concept:-

Surface, area and volumes

Let's Do!

What we need to know is :-

$\rm{Volume \ of \ Cylinder = \pi \times r^2 \times height}$

This can be also written as :-

$\rm{Volume \ of \ Cylinder = Area \ of \ the \ base \times height}$

So, following the notions of the given formula we need to place the values,

$\rm{Volume \ of \ Cylinder = 120 \times 15}$

So, we get the volume of the cylinder as 1800 cm³.

Things to Note:-

• These types of questions occur less. So, we can also find the radius first in order to obtain the area.

This can be done as:-

$\rm{120 = \pi \times r^2}$

Taking value of pi as 22/7, we get

$\rm{\dfrac{120 \times 7}{22} = r^2}$

$\rm{\sqrt{\dfrac{120 \times 7}{22}} = r}$

Well, we can see it has a complicated architecture, so we can use the above method.

Answer 2

Question :-

• The area of the base of a cylinder is 120 sq.cm. Find the volume if its height is 15cm.

Given :-

• Area of the Base = 120sq.cm
• Height of the Cylinder = 15cm

To Find :-

• Volume of the Cylinder .

Solution :-

${:} \longrightarrow \sf \boxed{\bf{Volume \: of \: Cylinder \: = \: Area \: of \: the \: Base \: \times \: Height }}$

$\quad {:} \longrightarrow \sf{\sf{Volume \: of \: Cylinder \: = \: 120\: \times \: 15 }}$

$\quad {:} \longrightarrow \sf{\bf{Volume \: of \: Cylinder \: = \: 1800cm^{3} }}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{Volume \: of \: Cylinder \: = \underline {\underline{ 1800cm^{3}}}}\\\end{gathered}\end{gathered}$

━━━━━━━━━━━━━━━━━━━━━━━━━

More For Knowledge :-

$\boxed{\begin{minipage}{6.2 cm}\bigstar \:\underline{\textbf{Formulae Related to Cylinder :}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} \:Area\:of\:Base\:and\:top =\pi r^2 \\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:Curved \: Surface \: Area =2 \pi rh\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Total \: Surface \: Area = 2 \pi r(h + r)\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Volume=\pi r^2h\end{minipage}}$

━━━━━━━━━━━━━━━━━━━━━━━━━