Question

3. The base of an isosceles triangle is 4/cm. The perimeter of the triangle is 4*2/15 cm.What is the length of either of the remaining equal sides?
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Answer 1

Step-by-step explanation:

base=BC=4/3cm

letAB=x

soBC=x(two sides of isosceles triangle are equal)

perimeter = 4*2/15cm

=4×15+2/15

=60+2/15

=62/15

perimeter = sum of sides

62/15=AB+AC+BC

62/15=X+X+4/3

62/152X+4/3

2X+4/3=62/15

2X=62/15-4/3

2X=62-4×5/15

2X=62-20/15

2X=42/15

X=42/15×1/2

X=21/15

X=7/5

X=1*2/5

Length of remaining 2 sides=1*2/5