Question

3. The base of an isosceles triangle is cm. The perimeter of the triangle is 62 by 50
What is the length of either of the remaining equal sides ?​

Answer 1

Answer:

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Answer 2

Base of isosceles triangle = 4/3 cm

Perimeter of triangle = 62/15 cm

Let the length of equal sides of triangle be x.

According to the question,

4/3 + x + x = 62/15 cm

⇒ 2x = (62/15 – 4/3) cm

⇒ 2x = (62 – 20)/15 cm

⇒ 2x = 42/15 cm

⇒ x = (42/30) × (½)

⇒ x = 42/30 cm

⇒ x = 7/5 cm

The length of either of the remaining equal sides are 7/5 cm.