Question

3) The bob of a simple pendalam of length in
hand mass loog & a speed of 1.4 mile at the
lowest point in its path find the tension in
the string
moment. Take
at thing
9 = 9.8 m/s2​

Answer 1

Explanation:

Given:

The length of the simple pendulum is r=1m

The mass of the bob is m=0.1kg

The speed of the bob at the lowest point is v=1.4m/s

AT the lowest point, the weight of the bob and the centripetal force combines to gives the tension developed in the string.

T=Mg+

r

Mv

2

T=(0.1×9.8)+(

1

0.1×1.4

2

)

T=1.176N

Answer 2

${\huge{\bold{\underline{Answer:-}}}}$

T = mg Cos0 + mv^2 / r

=> T = 0.1 × 10 × Cos0 + 0.196

=> T = (1 - 0^/2) + 0.196

~ T = (1 - (0.2)^2/2) + 0.196

=> T = (1 - 0.02) + 0.196

~ T = 0.98 + 0.196

=> T = 0.98 + 0.196

~ T = 1.176N.

Hope it helps uh ❤︎