Question

3. The breadth of a rectangular garden is 3 m less than the length of
the garden. There is an isosceles triangular garden whose base is
same as the breadth of a rectangular garden and its altitude is 12
m. If the area of the rectangular garden is 4 m? more than the
area of the triangular garden, then find the length and breadth of
the rectangular garden.​

Answer 1

Answer:

Let The Length And Breadth of the garden be X and Y respectively

Then,

X-3=Y

Y=Base Of Isosceles Triangle

Height Of Triangle=12m

Area Of Rectangular Garden = X*Y

Area Of Isosceles Triangle= 1/2*Y*12

Step-by-step explanation:

ar of Rectangular Garden = X(X-3)

X^2 - 3x ........(1)

ar of triangle = Y*6

(X-3)6

6x - 18 ..........(2)

ACT,

Ar Of Rectangular Garden = 4 + Ar Of Triangle

X^2 - 3x = 4 + 6x - 18

X^2 - 3x = 6x - 14

X^2 - 9x + 14 = 0

X^2 - 7x - 2x + 14 = 0

X (X-7) - 2 (X-7) = 0

X = 7 Or X = 2

Therefore

If X = 7

Then Y = 4