Question

3. The car parking charges for 1 hour is * 40. Find the parking charges for 16 hours.​

Answer 1

Answer:

This is the solution.

Hope this helps you.

Answer 2

ANSWER

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupees

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.Let assume number of hours be represented by variable x.

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.Let assume number of hours be represented by variable x.As for first two hours parking charges is 50,

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.Let assume number of hours be represented by variable x.As for first two hours parking charges is 50, So remaining subsequent hours are x-2

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.Let assume number of hours be represented by variable x.As for first two hours parking charges is 50, So remaining subsequent hours are x-2 And as charges for 1 subsequent hour = Rs 10

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.Let assume number of hours be represented by variable x.As for first two hours parking charges is 50, So remaining subsequent hours are x-2 And as charges for 1 subsequent hour = Rs 10 So charges for x-2 hrs = (x - 2) \times 10 = 10x - 20(x−2)×10=10x−20

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.Let assume number of hours be represented by variable x.As for first two hours parking charges is 50, So remaining subsequent hours are x-2 And as charges for 1 subsequent hour = Rs 10 So charges for x-2 hrs = (x - 2) \times 10 = 10x - 20(x−2)×10=10x−20So total charges of parking for x hours = first two hours parking charges + charges for x-2 hrs = 50 + 10x – 20 = 10x + 30

Parking charges of a car in hyderabad railway station for first 2 hours = 50 rupeesAnd 10 rupees for each subsequent hour Need to write the equation for this.Let assume number of hours be represented by variable x.As for first two hours parking charges is 50, So remaining subsequent hours are x-2 And as charges for 1 subsequent hour = Rs 10 So charges for x-2 hrs = (x - 2) \times 10 = 10x - 20(x−2)×10=10x−20So total charges of parking for x hours = first two hours parking charges + charges for x-2 hrs = 50 + 10x – 20 = 10x + 30Hence equation representing parking charges for x hours is 10x + 30

MARK ME AS BRAINLIST

HOPE YOU LIKE