Question

3. The change in velocity of a particle moving in a straight line with constant acceleration in the time
interval from t = 4sec to t 6sec in 12 m/s. The acceleration of the particle is
a) 6 m/s
b) 4 m/s
02 m/s​

Answer 1

Answer:

Option a, 6 m/s

Explanation:

Acceleration=(v-u)/t

You are provided the change in velocity ∆v= 12 m/s

So let us find acceleration:-

Time interval= 6s-4s= 2s

So we have to find acceleration in 2 seconds

that is,

a= ∆v/t

=12/2= 6 m/s

I hope that u got it!!!