Question

3 The diagonals of a rhombus are 12 cm and 16 cm. Find the area and also the length of the sides of the
rhombus. (Hint: Use Pythagoras theorem for finding the side.)
4 A diagonal of a quadrilateral is 16 m. The off-sets are 6 m and 8 m. What is the area of the​

Answer 1

Step-by-step explanation:

I will not use phythagoras formula but other metord

area of rhombus = 1/2 × diagonal 1 × diagonal2

1/2×12×16

96

area = 96 CM square

Answer 2

Step-by-step explanation:

The diagonals of a rhombus are 12 cm and 16 cm. What is the area and also the length of the sides of the rhombus?

Area of rhombus = 1/2(Product of diagonals)

Area = 1/2(12*16)

= 96 cm^2

Diagonals of rhombus are perpendicular bisects each other so in as per this property a right angled triangle formed so by Pythagoras theorem side of rhombus will be hypotenuse of that triangle

side will be

H^2= 6^2 + 8^2

36+64 = 100

side= 10 cm