Question

3. the difference of the present ages of brother and his younger sister 5 years. The
product of ages of numerical value is equal to 6 times the sum of their ages.
Find the present ages of the brother and his sister.​

Answer 1

Answer:

sister 6

younger brother 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let sister's age=x and brother's age=y

y-x=5...... (1)

xy=6 (x+y)......(2)

From equation (1)......y=5+x

Put value of y in (2)equation......x (5+x)=6 (x+5+x)

=5x+xx=12x+30

=xx-7x-30=0

Factor......xx-10x+3x-30=0

x(x-10)+3(x-10)=0

(x+3) (x-10)=0

x=10 years (sister's age)

brother's age=10+5=15 years