Math, asked by annurunipur, 9 months ago




3. The digit in tens Place of a 2- digit numbe
is twice that of the units digit. if the
are reversed, the neue number bi
18 less than the Original
number, find
Original
nal number​

Answers

Answered by Donster
0

Answer:

The digit at the ten’s place of a two digit number is twice the digit at the unit’s place. If the sum of this number and the number formed by reversing the digits is 66. Find the number?

4 Answers

Gopal Menon, B Sc (Hons) Mathematics, Indira Gandhi National Open University (2010)

Answered May 14, 2019·Author has4.8Kanswers and3.1Manswer views

Let the digit in the unit’s place be x.x.

The digit in the ten’s place is twice the digit in the unit’s place.

⇒⇒ The digit in the ten’s place is 2x.2x.

⇒⇒ The number is 2x×10+x=21x.2x×10+x=21x.

⇒⇒ The number formed by reversing the digits is x×10+2x=12x.x×10+2x=12x.

⇒⇒ The sum of the number and the number formed by reversing the digits is 21x+12x=33x.21x+12x=33x.

It is given that the sum of the number and the number formed by reversing the digits is 66.66.

⇒33x=66⇒x=2⇒2x=4.⇒33x=66⇒x=2⇒2x=4.

⇒⇒ The number is 42.

Step-by-step explanation:

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Answered by sunitapanda8131448
0

Answer:

2 is the originally number

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