3. The displacement in meter of a particle moving along x-axis is given by x= 10t +2t2. Calculate the initial velocity and initial acceleration of the particle.
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x=5t
2
+18t
(1)v=
dt
dx
=10t+18
att=2s,v=10×2+18=38m/s
(2)Average,velocity=
time
displacement
att=2,x=5(2)
2
+18×2=56m
t=3,x=5(3)
2
+18×3=99m
Averagevelocity=
3−2
99−56
=43 m/s
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