Chemistry, asked by shaikhsafwan7865, 8 months ago

دیا
3 The dissociation Constant of bezoic acid
(Colo CooH) is 6.6 x los calculate than
hydrogen ion concentration of a Solution
Containing 1.22 gm of benzoic acid in 2000ml
of coater​

Answers

Answered by shivkr1234
0

Explanation:

Since pH=3.19

[H

3

O

+

]=6.46×10

−4

M

C

6

H

5

COOH+H

2

O⇋C

6

H

5

COO

+H

3

O

K

a

=

[C

6

H

5

COOH]

[C

6

H

5

COO

][H

3

O

+

]

[C

6

H

5

COO

]

[C

6

H

5

COOH]

=

K

a

[H

3

O

+

]

=

6.46×10

−5

6.46×10

−4

=10

Let the solubility of C

6

H

5

COOAg be x mol/L

Then,

[Ag

+

]=x

[C

6

H

5

COOH]+[C

6

H

5

COO

]=x

10[C

6

H

5

COO

]+[C

6

H

5

COO

]=x

[C

6

H

5

COO

]=

11

x

K

sp

[AG

+

][C

6

H

5

COO

]

2.5×10

−13

=x(

11

x

)

x=1.66×10

−6

mol/L

Thus, the solubility of silver benzoate in a pH 3.19 solution is 1.66×10

−6

mol/L

Now, let the solubility of C

6

H

5

COOAg be x

M

Then, [Ag

+

]=x

M and [C

6

H

5

COO

]=x

M

K

sp

=[Ag

+

][C

6

H

5

COO

]

K

sp

=(x

)

2

x

=

K

sp

=

2.5×10

−13

=5×10

−7

mol/L

x

x

=

5×10

−7

1.66×10

−6

=3.32

Hence, C

6

H

5

COOAg is approximately 3.32 times more soluble in low pH solution.

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