Question

3. The distance between Akola and Bhusaval is 168 km. An express train takes 1 hour less than a passenger train to cover that distance. Find the average speed of each train, if the average speed of the express train is more by 14 km/h than the speed of the passenger train.​

Answer 1

Step-by-step explanation:

The distance between Akola and Bhusawal is 168 km. Suppose, average speed of passenger train is x km/hr.

∴ the average speed of express train is (x + 14) km/hr.

∴ the time required for passenger train = 168 / x hours and the time required for express train = 168 / x +14 hours

∴ from the given condition,

∴ x2 + 14x = 168 × 14

∴ x2 + 14x - 2352 = 0

∴ x2 + 56x - 42x -2352 = 0

∴ x(x + 56) - 42(x + 56) = 0

∴ x(x + 56)(x - 42) = 0

∴ x + 56 = 0 or x - 42 = 0

∴ x = - 56 or x = 42 But speed is not negative x

∴ average speed of passenger train = 42 km/hr and average speed of express train = (42 + 14) = 56 km/hr.