Physics, asked by shindemanisha41072, 10 months ago

3. The distance travelled by a particle starting from rest
and moving with an acceleration 4 ms –2, in the third.
second is
(A)10/3
(b) 19/3
10) 6 m
(d) 4 m

Answers

Answered by subha1645
3

Answer:

10/3

Explanation:

s=ut+ 1/2a (2n-1)

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