3. The energy used by the electric geyser for
30 minutes is 44 kJ, at a voltage of 250 V
How large is the current flow through the
electric geyser?
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Answer:
P = 500;
U = 250U
we known, P = UI
therefore I = P / V; = 1500/250=6A
NOW, E = PT =1*5K omega^ * r 0 Cost kw h; = 75^ * 6 - 450 24xy = 75kwh = 75 Cost for I unit Rupees Rupees
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