Question

3 The equation of the lines which pass through the origin and are inclined at an
angle tan^-1(m) to the line y = mx+c , are​

Answer 1

Answer:

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Step-by-step explanation:

If θ is the angle involved, then we have tan θ=m

Here, let m1 be the slope of lines we have to find, then using m2=m , which is the slope of the given line; we have

tan θ=m1−m1+m1m=±m

Solving the 2 cases, we get m1=2m1−m2 and m1=0

Now, the lines are passing through the origin. So y -intercept = 0

Answer: y=2mx1−m2 and y=0

Answer 2

Answer:

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