Question

3.
The equation whose roots are 1, 2+3i is
1)x - 4x²+x+6=0
2) x - x2 – 3x + 3 = 0
3) r? - 4x² – 8x+8 = 0
4) x - 5x² +17x-13 = 0​

Answer 1

Answer:

option B is the answer..........

Step-by-step explanation:

x

3

−4x

2

−8x+8

suppose,

y=x

3

−4x

2

−8x+8

andreplaceywith0.

x

3

−4x

2

−8x+8=0

Now,factorizingtheequ:

(x+2)(x

2

−6x+4)=0

⇒x+2=0

∴x=−2

and,

x

2

−6x+4=0[usingquadraticformula=−

2a

b±

b

2

−4(ac)

substitutethevalues&findthevalueofx:

a=1,b=−6,c=4

⇒x=

2.1

−6±

(−6)

2

−4(1)(4)

=

2

6±

36−16

=

2

6±

20

=

2

6±2

5

=3±

5

∴x=3+

5

,3−

5

so,thatwecansaythevalueofx=−2,3+

5

,3−

5

orx=−2,3±

5

AndthecorrectoptionisB.