3. The exterior angle of a regular polygon is one-fifth of its interior angle. How many sides have the polygon?
Answers
Step-by-step explanation:
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.so in the question here, the given information says the following:
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.so in the question here, the given information says the following:360n360n = 15⋅180(n−2)n15⋅180(n−2)n
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.so in the question here, the given information says the following:360n360n = 15⋅180(n−2)n15⋅180(n−2)n solve for n to find the number of sides.
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.so in the question here, the given information says the following:360n360n = 15⋅180(n−2)n15⋅180(n−2)n solve for n to find the number of sides.cross multiply maybe….
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.so in the question here, the given information says the following:360n360n = 15⋅180(n−2)n15⋅180(n−2)n solve for n to find the number of sides.cross multiply maybe….180n(n-2) = (360)(5n)
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.so in the question here, the given information says the following:360n360n = 15⋅180(n−2)n15⋅180(n−2)n solve for n to find the number of sides.cross multiply maybe….180n(n-2) = (360)(5n)(n-2) = (2)(5)
the sum of the exterior angles of a polygon with n sides is always 360° - for any integer, n. so each of the n exterior angles individually would measure 360n360n °.The sum of the interior angles of a polygon with n sides depends on the value of n, (the number of sides). The sum of interior angles is 180(n-2)°, so each interior angle is equal to 180(n−2)n180(n−2)n °.so in the question here, the given information says the following:360n360n = 15⋅180(n−2)n15⋅180(n−2)n solve for n to find the number of sides.cross multiply maybe….180n(n-2) = (360)(5n)(n-2) = (2)(5)n-2 = 10
n=10
Polygon has 12 sides.