3) The first term of an A.P. is 3. Common difference is 6, Complete the activity to find the 10 th term of this A.P.
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Answer:
Given a=6,d=3.
S
n
=
2
n
[
2a
+(n−1)d]
S
27
=
2
27
[12+(27−1)
(3)
]
=
2
27
[12+26×3]
=
2
27
[12+78]
=
2
27
[
90
]
=27×45
∴S
27
=
1215
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