Math, asked by navs79656, 6 months ago

3
The floor of sectangulat hall has a
Rs 10 per m2 s 15000 find the height of the wall
of painting the four walls at the sada
2 / 4th]
If the Cost
le
Hall - 250m =​

Answers

Answered by pardeepsingla80
0

Answer:

Perimeter of rectangular hall = 2(l + b) = 250 m

Total cost of painting = Rs.15000

Rate per m2 = Rs.10

Area of four walls = 2(l + b) h m2 = (250×h) m2

A/q,

(250×h)×10 = Rs.15000

⇒ 2500×h = Rs.15000  

⇒ h = 15000/2500 m

⇒ h = 6 m  

Thus the height of the hall is 6 m.

Step-by-step explanation:

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