Question

3. The foot of a ladder rests against a wall and its top is held by a tie rope as shown in the figure below. The ladder weighs 100N, and center of gravity is 0.40m length from the foot. A 150N Child hangs from a rung that is 0.20 of length from the top. Determine the tension in the tie rope and the components of the force on the foot of the ladder

Answer 1

Completing Question : Length of ladder 1m
Angle made by ladder with the vertical is (theta) .

Final Answer :
$160 \tan( \theta) \: units$
Horizontal Component of force acting on the foot of ladder : = Tension of rope
Vertical Component : 250N
Steps and Understanding :
1) System is in Equilibrium,
So Net Torque about any point is 0 .

2) Let that point be Foot of ladder.
There are forced which are giving torque to ladder.
Tension
Force applied by Child
Gravitational force.

3) We will make out ne+ torque 0 to find the value of Tension.

For Calculation see pic.