3. The given fig. 15.14 is a circle with centre O and
angle AOB = 90° and OA = 3 cm, then find the area
of the shaded region.
Fig. 15.14
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Step-by-step explanation:
AO=BO=3CM
AREA OF A TRIANGLE= (1/2)bh
=1/2× 3×3
=1/2×9
=4.5cm²
theta=90°=π/2
AREA OF A SECTOR= 1/2 r² theta
=1/2×9×π/2
=1/2×9×22/14
≈7 cm²
Area of shaded part= 7- 4.5
= 2.5cm²
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