Physics, asked by jagritisahu271, 2 months ago

3. The Hall coefficient of a metal is low. It means that:
(a) the charge carrier density in metal is high
(b) the charge carrier density in metal is low
(c) the Hall field produced in metal is high
(d) the conductivity of the metal is zero​

Answers

Answered by riddhitrivedi842
4

Explanation:

The Hall coefficient (RH), mobility (μH) and carrier concentration (nH) was found to be dependent on composition and thickness of the films. ... The increase of film thickness increases Hall coefficient (RH) and mobility (μH) while the carrier concentration (nH) decreases.

Answered by krishna210398
0

Answer:

The correct answer is (b) the charge carrier density in metal is low.

Explanation:

The hall impact is a magnetic sensitivity impact. commonly, a magnetic subject with a magnetic induction intensity of B is carried out in the period X direction of a semiconductor wafer, and an electromotive pressure UH is generated in the width Y path. This phenomenon is called the hall effect. UH is known as the corridor potential, and its length may be expressed as: UH = RH / d * IC * B (1) within the formulation, RH is referred to as the corridor coefficient and is decided with the aid of the properties of the conductor fabric; d is the thickness of the conductor material, IC Is the present day depth, and B is the magnetic induction depth. Set RH / d = k, then formula (1) can be written as: UH = ok * IC * B (2) it can be seen that the corridor voltage is proportional to the manufactured from the manipulate current and the magnetic induction intensity. ok is referred to as the bigger the hall coefficient value , The higher the sensitivity; the smaller the aspect thickness, the more the output voltage. hall coefficient: inside the formulation okay = 1 / (n * q), n is the provider density. typically, the carrier density in metals may be very huge, so the corridor coefficient of steel materials could be very small, and the corridor impact isn't always apparent; The density of providers in semiconductors is a good deal smaller than that of metals, so the hall coefficient of semiconductors is lots large than that of metals, that may produce a bigger hall effect. consequently, hall factors do not use metallic materials however semiconductors.

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